CentOS

hello, i'm new to linux, and just trying to create script.
i have create script to delete files in several folders that is older than x days, so i create it like this:

Code: Select all

#!/bin/bash
find /pathtofolder/* -type f -mtime +7 -exec rm {} \;
find /pathtofolder/* -type f -mtime +7 -exec rm {} \;

the result is error:

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find: missing argument to `-exec'
find: missing argument to `-exec'

can anyone help?

Use -delete instead of -exec rm {} \;

And you probably don't want the * on the end of the path either, find already traverses all subdirectories unless you tell it not to.

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find /path to folder/ -type f -mtime +7 -delete;
find /path to folder/ -type f -mtime +7 -delete;

created error: command not found

btw it works when i run the command perline directly in the terminal, but error when in the script

Does it work without the semicolon? Or maybe use the full path of find, /usr/bin/find.

removing the semicolon produce error: 'usr/bin/find: unknown predicate `-delete

What is the output from rpm -q centos-release and from uname -a ?

nevermind, I found the issue, it is the $'\r' error, after i use bash -x command.
this seems to happen because i create the script in windows using notepad++.
to fix that i need to convert it to linux format using menu: Edit -> EOL conversion -> Unix/OSX format.

thanks to the quick responses.

CentOS

script with multiple line of find, error find: missing argument to `-exec'

script with multiple line of find, error find: missing argument to `-exec'

Re: script with multiple line of find, error find: missing argument to `-exec'

Re: script with multiple line of find, error find: missing argument to `-exec'

Re: script with multiple line of find, error find: missing argument to `-exec'

Re: script with multiple line of find, error find: missing argument to `-exec'

Re: script with multiple line of find, error find: missing argument to `-exec'

Re: script with multiple line of find, error find: missing argument to `-exec'