awk - Korn shell or Bash. Order the output by the absolute pathname of the shell used.

[lse123new]

AS SELF STUDY LEARNER I TRIED SOLVE THIS IN AWK CHAPTER OF MY LINUX/UNIX BOOK

12.1 Display from /etc/passwd a list of users and their shells for those using the
Korn shell or Bash. Order the output by the absolute pathname of the shell used.
I came with this ... but sort missing - any help can provided ...? Cent OS 7

awk -F: '($7 ~ /bash/ || $7 ~ /korn/)' /etc/passwd

[tunk]

Does this work:
awk -F: '($7 ~ /bash/ || $7 ~ /korn/)' /etc/passwd | sort -t: -k7
BTW: korn is /bin/ksh

[lse123new]

[bob@server1 ~]$ awk -F: '($7 ~ /bash/ || $7 ~ /halt/)' /etc/passwd | sort -t: -k7
bob1005:1006::/home/bob:/bin/bash
root0:0:root:/root:/bin/bash
tux1000:1000:tux:/home/tux:/bin/bash
halt7:0:halt:/sbin:/sbin/halt
[bob@server1 ~]$


MUST WORKED THANKS
I did Not have ksh and put halt that had

[lse123new]

[bob@server1 ~]$ awk -F: '($7 ~ /bash/ || $7 ~ /halt/)' /etc/passwd | sort -t: -k3
root0:0:root:/root:/bin/bash
tux1000:1000:tux:/home/tux:/bin/bash
bob1005:1006::/home/bob:/bin/bash
halt7:0:halt:/sbin:/sbin/halt
[bob@server1 ~]$

[TrevorH]

Though that's not strictly doing what the question asked: "Display from /etc/passwd a list of users and their shells". Yes, the info they ask for is there but you are also displaying the entire line not jsut those 2 requested fields.